4.6.2 Indeks, Surd dan Logaritma, SPM Praktis (Soalan Pendek) January 23, 2022May 9, 2020 by Soalan 5: Selesaikan persamaan, log 9 ( x − 2 ) = log 3 2 Penyelesaian: log 9 ( x − 2 ) = log 3 2 log a b = log c b log c a ⇒ log 3 ( x − 2 ) log 3 9 = log 3 2 log 3 ( x − 2 ) 2 = log 3 2 log 3 ( x − 2 ) = 2 log 3 2 log 3 ( x − 2 ) = log 3 2 2 x − 2 = 4 x = 6 Soalan 6: Selesaikan persamaan, log 9 ( 2 x + 12 ) = log 3 ( x + 2 ) Penyelesaian: log 9 ( 2 x + 12 ) = log 3 ( x + 2 ) log 3 ( 2 x + 12 ) log 3 9 = log 3 ( x + 2 ) log 3 ( 2 x + 12 ) = 2 log 3 ( x + 2 ) log 3 ( 2 x + 12 ) = log 3 ( x + 2 ) 2 2 x + 12 = x 2 + 4 x + 4 x 2 + 2 x − 8 = 0 ( x + 4 ) ( x − 2 ) = 0 x = − 4 (tidak diterima) x = 2 Soalan 7: Selesaikan persamaan, log 4 x = 3 2 log 2 3 Penyelesaian: log 4 x = 3 2 log 2 3 log 2 x log 2 4 = 3 2 log 2 3 log 2 x 2 = 3 2 log 2 3 log 2 x = 2 × 3 2 log 2 3 log 2 x = 3 log 2 3 log 2 x = log 2 3 3 x = 27 Soalan 8: Selesaikan persamaan, 2 log 5 2 = log 2 ( 2 − x ) Penyelesaian: 2 log 5 2 = log 2 ( 2 − x ) 2 = log 5 2. log 2 ( 2 − x ) 2 = 1 log 2 5 . log 2 ( 2 − x ) 2 log 2 5 = log 2 ( 2 − x ) log 2 5 2 = log 2 ( 2 − x ) 25 = 2 − x x = − 23